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Question Let M(t) = (1/6)e^t (2/6)e^2t (3/6)e^3t Find The Followinga E(Y)b V(Y)c The Distribution Of Y This problem has been solved!(X Y )t= EeXt Ee Yt = M X1 (t m) M n (t)M Y1 (t n) M n (t n) = em( 1 t m 1 2 ˙2 t 2 m)e n( t n 1 ˙2 t 2 n 2) = et( 1 ) 1 2 t2(˙2 m ˙2 2 n) This is the moment generating function of a normal random variable with mean 1 2 and variance ˙2 1 m ˙ 2 2 n d It is given that n= mand ˙2 1 = 2;˙ 2 2 = 25 We want P( 1Watch anywhere, anytime, on an unlimited number of devices Sign in with your Netflix account to watch instantly on the web at netflixcom from your personal computer or on any internetconnected device that offers the Netflix app, including smart TVs, smartphones, tablets, streaming media players and game consoles

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Best Answer By the definition of the moment generating function, m (t)=E (e^tY) This is the sum of e^ty over all y in Y view the full answerB If W = 3 Y , show that the momentgenerating function of W is m ( 3 t ) c If X = Y − 2, showY″ = y Obviously y1 = e t is a solution, and so is any constant multiple of it, C1 e t Not as obvious, but still easy to see, is that y 2 = e −t is another solution (and so is any function of the form C2 e −t) It can be easily verified that any function of the form y = C1 e t C 2 e −t will satisfy the equation In fact, this is the

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